Question

A 15m long ladder reached a window 12m high from the ground on placing it against a wall at a distance a meters from the wall.find the distance of the foot of the ladder from the wall. With diagram

Answer 1

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Answer 2

Question

A 15m long ladder reached a window 12m high from the ground on placing it against a wall at a distance. Find the distance of the foot of the ladder from the wall.

Answer

For this we must apply Pythagorean Therom.

• So the question arises why do we need to solve with Pythagorean Therom? This is because the wall is straight and the ladder and ground with the wall forms a right angle triangle. So here the hypotenuse and base is given. We must find the height.

Pythagorean Therom ⇒

$Base² + Height² = Hypotenuse²$

$⇒ 12² + Height² = 15² \\ </p><p></p><p>⇒ 144 + Height² = 225 \\ </p><p></p><p>⇒ Height² = 225 - 144 \\ </p><p></p><p>⇒ Height² = 81 \\ </p><p></p><p>⇒ Height = √81 \\ </p><p></p><p>⇒ Height = 9m$

∴The distance of the foot of the ladder from the wall is 9m.

Additional Information

• Triangle is a closed polygon that consists of three vertices, sides and angles.

• There are three types of triangles on the basis of sides. They are ⇒

• Scalene ⇒ All the sides of this Triangle are of different measures.
• Isosceles ⇒ Two sides of this Triangle is same.
• Equilateral ⇒ All sides have the same measure.

• There are three triangles of the basis of angles. They are ⇒

• Right Angled ⇒ This Triangle consists of one right angle.
• Obtuse ⇒ This Triangle consists of one obtuse angle.
• Acute ⇒ All angles are acute angles in this Triangle.

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