a 15m long ladder reaches a window 12m high from the room on placing it against a wall. How far is the ladder from wall
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By Pythagoras theorem,
15²=base²+12²
225=base²+144
225-144=base²
√81=base
9=base=distance of ladder base from the wall
15²=base²+12²
225=base²+144
225-144=base²
√81=base
9=base=distance of ladder base from the wall
Answered by
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hiii!!!
here's ur answer...
given the length of the ladder is 15m and it's 12m high from the ground.
by Pythagoras thereom we will find the length between the ladder and the wall in the ground.
let the hypenotuse be the length of the ladder=15m and it's height is 12m.
→a²+b²=c²
→12²+b²=15²
→144+b²=225
→b²=225-144
→b²=81
→b=√81
→b=9
hence the length of the base(length of ladder far from the ground) is 9m.
hope this helps..!
here's ur answer...
given the length of the ladder is 15m and it's 12m high from the ground.
by Pythagoras thereom we will find the length between the ladder and the wall in the ground.
let the hypenotuse be the length of the ladder=15m and it's height is 12m.
→a²+b²=c²
→12²+b²=15²
→144+b²=225
→b²=225-144
→b²=81
→b=√81
→b=9
hence the length of the base(length of ladder far from the ground) is 9m.
hope this helps..!
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