Question

A 16 kg block moving on a frictionless horizontal surface with velocity 5 m/s compresses an ideal spring

and comes to rest. If the force constant of spring be 100 N/m, then how much is the spring compressed?​

Answer 1

Answer:

The answer is 1.6m 16 kg block moving on a frictionless horizontal surface with velocity 5 m/s compresses an ideal spring

and comes to rest. If the force constant of spring be 100 N/m, then how much is the spring compressed?

Answer 2

Answer:

A 16 kg block compresses an ideal spring  and comes to rest. If the force constant of spring is 100 N/m, then spring compressed distance is $1.5m$

Explanation:

• The restoring force on a spring of spring constant (K) when elongated to a distance (x) is given as $F=-Kx$

• Due to the mass (m) attached to the spring the gravitational force on the mass is  $F=mg$

        where $g=9.8m/s^{2}$(acceleration due to gravity)

• at equilibrium condition  both the forces are equal, that is $-Kx=mg$

From the question, we have

mass attached $m=16kg$

spring constant $K=100N/m$

stretched length $x=mg/K$

put the given values

⇒$x=\frac{16*9.8}{100} =1.5m$