Question

A 16 ohm resistance wire is bent to form a square. A source of emf 9 volt is connected across one of its sides. Calculate the potential difference across any one of its diagonals. Please give appropriate and right answer please don't copyright

Answer 1

Given:

A 16 ohm resistance wire is bent to form a square. A source of emf 9 volt is connected across one of its sides.

To find:

Potential Difference across the diagonals ?

Calculation:

Since the wire is divided into 4 equal sides , each side will have resistance = 16/4 = 4 ohm (see Diagram).

Now, first let's calculate the current through circuit:

$\therefore \: i = \dfrac{voltage}{ r_{eq} }$

$\implies \: i = \dfrac{9}{ \bigg( \dfrac{4 \times 12}{4 + 12} \bigg)}$

$\implies \: i = \dfrac{9}{ \bigg( \dfrac{48}{16} \bigg)}$

$\implies \: i = \dfrac{9}{ \bigg( 3 \bigg)}$

$\implies \: i = 3 \: amp$

Now, let's calculate the potential difference:

$\therefore \: V_{A} - 4r - 4r = V_{B}$

$\implies \: V_{A} - 8r = V_{B}$

$\implies \: V_{A} - V_{B} = 8r$

$\implies \: \Delta V = 8(4)$

$\implies \: \Delta V = 32 \: volts$

So, potential difference between diagonals is 32 Volts.