Question

a 1600 kg load is lifted using a simple machine having a velocity ratio of 5. what will be the efficiency of the machine if effort applied is 400kg:

Answer 1

Answer:

Step-by-step explanation:

1600-----------------5

400-------------------x

1600*x=400*5

x=400*5/1600

=1.25

Answer 2

Load (L)=1600 kg

Effort(E)= 400 kg

Velocity Ratio (VR)=5

Efficiency = ?

Firstly,

Machanical advantage (MA) = Load/Effort

= 1600/400

=4

Then,

Efficiency= MA/VR*100%

= 4/5*100%

=80%

Efficiency of simple machine is 80%.

Hope it will help .. Mate