a 1600 kg load is lifted using a simple machine having a velocity ratio of 5. what will be the efficiency of the machine if effort applied is 400kg:
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Answered by
0
Answer:
Step-by-step explanation:
1600-----------------5
400-------------------x
1600*x=400*5
x=400*5/1600
=1.25
nknavaneethan2:
no
Answered by
5
Load (L)=1600 kg
Effort(E)= 400 kg
Velocity Ratio (VR)=5
Efficiency = ?
Firstly,
Machanical advantage (MA) = Load/Effort
= 1600/400
=4
Then,
Efficiency= MA/VR*100%
= 4/5*100%
=80%
Efficiency of simple machine is 80%.
Hope it will help .. Mate
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