Question

a 16m deep well with diameter 3.5m is dug up and the earth out of it is spread evenly to form a plateform 27.5m by 7m . Find the height of the platform.​

Answer 1

Answer : 0.8 m✔✔

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Solution :

As we know that :

Well is in the shape of Cylinder

Given that :

Height of well = 16 m.

And Diameter = 3.5m => Radius = 3.5/2 = 1.75 m

Now, Volume of Well (Cylinder) :

$\pi {r}^{2} h \\ \\ = > \frac{22}{7} \times {(1.75)}^{2} \times 16....(1)$

Also Given that :

As the well spread evenly to form a plateform

Let, the height of plateform be x m.

Volume of plateform :

$27.5 \times 7 \times x = 192.5x$

ATQ :

$\frac{22}{7} \times {(1.75)}^{2} \times 16 = 192.5x \\ \\ = > x = \frac{22 \times 1.75 \times 1.75 \times 16}{7 \times 192.5} = 0.8$

So, the height of plateform will be 0.8 m. ✔

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Hope it helps ☺

Fóllòw Më ❤

Answer 2

Step-by-step explanation:

Volume of well = Volume of cuboidal platform

L×B×H = π × R²L'

H=0.799m = 0.8m (approx)