Question

A 17 m long ladder leans against a wall . if the foot of the ladder is 8 m away from the foot of the wall , find how far up the wall the ladder reaches.​

Answer 1

Answer:

A ladder 17m long rests against a vertical wall at a height of 15m above the ground. What is the distance between the foot of the ladder and the bottom of the wall?

This can be solved by Pythagoras’ theorem, the length of the ladder being the hypotenuse.

17^2 = 15^2 + x^2, where x is the distance between the foot of the ladder and the wall.

x^2 = 64

x = 8

So the distance between the foot of the ladder and the wall is 8m.

Answer 2

Step-by-step explanation:

Given: ladder = 17 m and base = 8 m

The ladder forms a right triangle with the base of 8 m, the wall will be 15 m and the ladder (hypotenuse) is 17 m.

Let’s say you did not know that this was a standard 8–15–17 right triangle.

This is how you can figure it out:

hypotenuse(h) 22 = side 2112 + side 2222

Let side 11 = base and side 22 = wall

17 22 = 8 22 + wall 22

wall = 172−82−−−−−−−√172−82

wall = 289−64−−−−−−−√289−64

wall = 225−−−√225

wall = 15 feet

>>>>>>>>>>15 feet