Question

A 175 m long train is travelling at the speed of 36 kmph. In how many seconds would it cross a bridge 625 m long

Answer 1

Solution:

Length of train = 175 m

Length of bridge = 625 m

Speed = 36 km/h = $36 * \frac{1000}{3600} = 36 * \frac{5}{18} = 2 * 5 = 10 \ m/s$

Total distance to travel = 175 + 625 = 800 m

We added length of train and bridge because as the train will cross the bridge fully it will have to travel its own length too.

$Speed = \frac{Distance}{Time}$

Time required for train to cross bridge = Total Distance/Speed

                                                                = 800/10

                                                                = 80 seconds

The time required by train to cross bridge will be 80 seconds or 1 minute 20 seconds.

Answer 2

Step-by-step explanation:

$\bf \huge \: Question \: \: \:$

• A 175 m long train is travelling at the speed of 36 kmph. In how many seconds would it cross a bridge 625 m long

___________________________

$\bf \huge \: \: Given \: \:$

• Length of train = 175 m

• Speed of train = 36 kmph

• Length of bridge = 625 m

___________________________

$\bf \huge \: \: To \: Find \:$

• how many seconds would it cross a bridge 625 m long

___________________________

$\bf \huge \: \: Solving\: \:$

$\tt \: time = 36 \times \frac{1000}{3600} \\ \\ \tt \: = > \frac{1000}{100} = 10m/s$

Total Distance :-

$</u></strong><strong><u>\tt \: = 175 \: m + 625</u></strong><strong><u>\: </u></strong><strong><u>m \:</u></strong><strong><u>$

$\tt \: On \: Adding \:$

$\tt \:=> 800M\:$

Speed = ?

we have formula :-

$</u></strong><strong><u>\tt</u></strong><strong><u> </u></strong><strong><u>speed</u></strong><strong><u> </u></strong><strong><u>=</u></strong><strong><u> </u></strong><strong><u>\</u></strong><strong><u>frac{</u></strong><strong><u>Total</u></strong><strong><u>\:</u></strong><strong><u>Dista</u></strong><strong><u>nce</u></strong><strong><u>}{</u></strong><strong><u>Time</u></strong><strong><u>}</u></strong><strong><u>\:$

$</u></strong><strong><u>\tt \: putting \: the \: all \: value \: </u></strong><strong><u>\:$

$\tt</u></strong><strong><u>{</u></strong><strong><u> </u></strong><strong><u>Speed</u></strong><strong><u> </u></strong><strong><u>=</u></strong><strong><u> </u></strong><strong><u>\</u></strong><strong><u>frac{</u></strong><strong><u>8</u></strong><strong><u>0</u></strong><strong><u>0</u></strong><strong><u>}{</u></strong><strong><u>1</u></strong><strong><u>0</u></strong><strong><u>}</u></strong><strong><u>}</u></strong><strong><u>\\ \\ </u></strong><strong><u>\:$

$\tt \: </u></strong><strong><u> \red</u></strong><strong><u>{</u></strong><strong><u>Speed</u></strong><strong><u> =</u></strong><strong><u>8</u></strong><strong><u>0</u></strong><strong><u>.</u></strong><strong><u>.</u></strong><strong><u>.</u></strong><strong><u> </u></strong><strong><u>secon</u></strong><strong><u>d</u></strong><strong><u> </u></strong><strong><u>}</u></strong><strong><u>\\ \\ </u></strong><strong><u>$

80 seconds would it cross a bridge 625 m long