Question

a) 18 ÷ ( – 6) + ( – 2) × 7
b) 2 ( – 5) (7) – 6 ÷ 3
c) (– 15 ÷ 5) + [ – 2 × ( – 8)] – 7
d) – 6 + 3 ( – 5) – 4
e) – 8 ÷ 4 – ( – 2) ( – 3)
f) ( 4 – 12) ÷ 2 [ 6 + ( – 9) ]
g) 19 – 5 × 4 (– 5) – 4 – 6
h) 9 × 2 + ( – 5) – 4 – 6
i) 21 – 3 × ( – 2) + ( – 9 ÷ 3)
j) 4 + ( – 6) × 2 – 15 ÷ 3

Answer 1

a. -17

b. -72

c. 6

d. -25

e. -8

f. 12

g. 109

h. 3

i. 24

j. -13

Answer 2

GIVEN,

a) 18 ÷ ( – 6) + ( – 2) × 7

b) 2 ( – 5) (7) – 6 ÷ 3

c) (– 15 ÷ 5) + [ – 2 × ( – 8)] – 7

d) – 6 + 3 ( – 5) – 4

e) – 8 ÷ 4 – ( – 2) ( – 3)

f) ( 4 – 12) ÷ 2 [ 6 + ( – 9) ]

g) 19 – 5 × 4 (– 5) – 4 – 6

h) 9 × 2 + ( – 5) – 4 – 6

i) 21 – 3 × ( – 2) + ( – 9 ÷ 3)

j) 4 + ( – 6) × 2 – 15 ÷ 3

TO FIND,

VALUES OF EQUATION.

SOLUTION,

SOLVING THE FOLLOWING EQUATIONS USING BODMAS RULES,

BODMAS = BRACKET-OF-DIVIDE-MULTIPLY-ADDITION-SUBSTRACTION.

A.

$=\frac{18}{-6} +(-2)*7\\\\=-3-2*7\\\\=-3-14\\\\=-17$

B.

$=2(-5)(7) -\frac{6}{3} \\\\= -70 -2\\\\=-72$

C.

$=\frac{-15}{5} + (-2*-8)-7\\\\=-3-16-7\\\\=-26$

D.

$=-6+3*-5-4\\\\=-6-15-4\\\\=-25$

E.

$=\frac{-8}{4} -(-2)(-3)\\\\= -2-6\\\\=-8$

F.

$=\frac{4-12}{2(6+(-9))}\\\\=\frac{-8}{-6}\\\\ =\frac{4}{3}$

G.

$=19-5*4(-5)-4-6\\\\= 19+100-10\\\\=109$

H.

$=9*2+(-5)-4-6\\\\=18-5-4-6\\\\=3$

I.

$=21-3*-2+\frac{-9}{3} \\\\=21+6-3\\\\=24$

J.

$=4-6*2-\frac{15}{3} \\\\=4-12-5\\\\=-13$

HENCE THE VALUES OF THE EQUATIONS ARE A=-17, B=-72, C=-26, D=-25, E=-8, F= 4/3, G=109, H=3, I=24, J=-13.