Question

A 18 m pole is supported by 2 guy wires attached to a point
2/3
of the way up the pole and to points on the ground 5m from the base of the pole. What is the length of each guy wire?
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Answer 1

Answer:

don't know sorry

Step-by-step explanation:

don't know sorry

Answer 2

Answer:

The pole is 18 m high and it is supported by two guy wires attached to a point \frac{2}{3}

3

2

of the way up the pole.

So, the point where the wires are attached is at (18 \times \frac{2}{3}) = 12(18×

3

2

)=12 meters height from the bottom.

Now, the wires are attached to the ground to points which are 5 m from the base of the pole.

So, the pole and the ground with the wire forms a right triangle where the wire lengths are the hypotenuse of the right triangles.

Applying the Pythagoras Theorem, the length of each guy wire will be = \sqrt{12^{2} + 5^{2}} = \sqrt{169} = 13

12

2

+5

2

=

169

=13 meters. (Answer)