Question

A=180-2A then evaluate 1-tan A/1+tan A
PLEASE ANSWER FAST EMERGENCY​

Answer 1

Answer:

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Step-by-step explanation:

Given tan2A=cot(A−18

0

)

⇒cot(90−2A)=cot(A−18

0

)[∵tanθ=cot(90−θ)]

Comparing angles we get

90−2A=A−18

⇒90+18=A+2A

⇒3A=108

⇒A=

3

108

hope it is helpful dear friend:)

⇒A=36

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