a 180 m long train crosses another 270 m long train running in the opposite direction in 10.8 s. if the speed of the first tain is 60 km/h, what is the speed of the second train in km/h?
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sum of the distance covered =450m
time=10.8
relative speed in op direction=60+s.
(60+s)*1000/3600=450/10.8
(60+s)*1000*10.8=450*3600
60+s=450*3600/10800
60+s=150
s=90
time=10.8
relative speed in op direction=60+s.
(60+s)*1000/3600=450/10.8
(60+s)*1000*10.8=450*3600
60+s=450*3600/10800
60+s=150
s=90
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3
Answer:
therefore answer is 90kmph
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