Question

(a) 1800
(b) 1600
(c) 1800 N
(d) 3200 NA
2. If mass of one atom is 3.32 x 10-23g, then calculate number of nucleons (neutrons an
protons) present in 2 atoms of the element :
(a) 40
(b) 20
(c) 10
(d) 40 NA​

Answer 1

Explanation:

Number of nucleon =MolarmassofnucleonMassofatom=1.6726×10−24g/nucleon3.32×10−23g=19.8=20(approximately)

Number of nucleon =MolarmassofnucleonMassofatom=1.6726×10−24g/nucleon3.32×10−23g=19.8=20(approximately)It is given that element comprises of 2 atoms 

Number of nucleon =MolarmassofnucleonMassofatom=1.6726×10−24g/nucleon3.32×10−23g=19.8=20(approximately)It is given that element comprises of 2 atoms Hence,number of nucleon = 2×20=40

Mark as BRAINLIST and Thanxxx