Question

A 1800 kg car is moving at 30m/s, when brakes are applied. If the average force exerted by the brakes is 6000 n, find the distance travelled by the car before it comes to rest.

Answer 1

Its a simple numerical .

it consists only two steps .

First , find out Deacceleration (Acceleration in opposite direction)

by using

$f = ma$

then find out Distance (S)

by using

$v {}^{2} - u ^{2} = 2as$

Answer 2

Given that,

Mass of car, m = 1800 kg

Initial speed, u = 30 m/s

Finally, it comes to stop, v = 0

Force, F = 6000 N

To find,

The distance travelled by the car before it comes to rest.

Solution,

The force acting on the car is given by :

$F=ma$

a is acceleration

$a=\dfrac{F}{m}\\\\a=\dfrac{6000\ N}{1800\ kg}\\\\a=3.34\ m/s^2$

Now using third equation to motion to find the distance travelled by the car before it comes to rest. So,

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0-(30)^2}{2\times 3.34}\\\\d=134.73\ m$

So, the distance travelled by the car before it comes to rest is 134.73 m.

Learn more,

Kinematics

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