Question

a 1800 kg car moving with speed of 20ms.if a superman stops the car in 0.5sec , what is the average force exerted by him on the car

Answer 1

Answer:

Explanation:

Given,

Initial velocity(u)=20ms  

−1

 

Final velocity(v)=0

Distance moved(S)=50m

We know,

v  2 =u  2  +2aS 0=20  2  +2a×50 −400=100a

a=  100 −400

​a=−4ms  −2

 

Now,

F=ma

F=1000×−4

=−4000N