Question

a
19. In a right-angled triangle POR, angle Q=90degree If Angle P =45 degree than value of tan p-cos square R is

Answer 1

Answer:

$\frac{1}{2}$

Explanation:

Q = 90°

P = 45°

So, R = 180° - (P + Q)

Or, R = 180° - 135°

Or, R = 45°

$\tan \:P - {cos}^{2} R$

$= \tan(45) - { \cos }^{2} (45)$

$= 1 - { (\frac{1}{ \sqrt{2} } )}^{2}$

$= 1 - \frac{1}{2}$

$= \frac{1}{2}$