A()1atma(g),hvap=460.6calmol1, boiling point = 50 k. What is the boiling point at 10 atm?
Answers
Answered by
0
Answer:Use clasius cleyperon equation
Explanation:
Log P1/p2 =∆Hvap/R(1/T1-1/T2)
Answered by
1
Explanation:
use clasious clapeyron equation you will get answer
Similar questions