Math, asked by devishichakraborty20, 9 months ago

[a^-1b^2/a^2b^-4]÷[a^3b^-5/a^-2b^3]=a^xb^y

Answers

Answered by mahalakshmi56

Step-by-step explanation:

Hey friend this is very easy one u can only solve it. If u don't get answer u can ask me

Answered by Anonymous

Answer:

Sorry mate please write it in mathematical Language.........sorry......not able to understand...... instead you can click a picture of your question.......☺️

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[a^-1b^2/a^2b^-4]÷[a^3b^-5/a^-2b^3]=a^xb^y​

Answers

[a^-1b^2/a^2b^-4]÷[a^3b^-5/a^-2b^3]=a^xb^y