Question

A 1Kg ball is thrown straight up in the air with an initial velocity of 30m/s. a. What is the kinetic energy of the ball when it is initially thrown? b. How much potential energy does the ball have at the top of its trajecto c. How high will the ball travel?​

Answer 1

a)Initial kinetic energy= 1/2 mu²

                                      =1/2 x 1 x 30 x 30

                                      =450J

c)Height: v²-u²=2gs

                0-30²=2x10xs

                  900=20s

                    s=900/20

                     s=45m

b)Potential energy=mgh

                               =1x10x45

                               =450J

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