A 1kg block is lifted vertically 1m by a boy the work done by the boy is
Answers
f=1kg.1m
=1j
I think this formula would be apply
other wise... one another is w=fs
A 1 kg block is lifted vertically 1 m by a boy the work done by the boy is
Solution:
we know that work done is W = FS
here F = force = ma
S = Displacement
m = mass of the object
a = g(gravitational acceleration) = 9.8 m/s² ≈ 10 m/s²
Now, by putting all the values in the formula
Work done by the boy = 1 kg X 10 m/s² X 1 m
= 10 kg.m²/s²
= 10 Joule
Alternative method
W = mgh
W = 1 kg X 10 m/s² X 1 m
= 10 kg.m²/s²
= 10 Joule
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