Question

A 1kg block is lifted vertically 1m by a boy the work done by the boy is

Answer 1

f=ma
f=1kg.1m
=1j
I think this formula would be apply
other wise... one another is w=fs

Answer 2

A 1 kg block is lifted vertically 1 m by a boy the work done by the boy is

Solution:

we know that work done is W = FS

here F = force = ma

        S = Displacement

        m = mass of the object

        a = g(gravitational acceleration) = 9.8 m/s² ≈ 10 m/s²                                                                                                                                                                                                                    

Now, by putting all the values in the formula

Work done by the boy = 1 kg X 10 m/s² X 1 m

                                      = 10 kg.m²/s²

                                      = 10 Joule

Alternative method

W = mgh

W = 1 kg X 10 m/s² X 1 m

    = 10 kg.m²/s²

    = 10 Joule

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