Question

A 1kg mass kinetic energy 1j what is speed

Answer 1

Answer:

$\large\bold\red{\sqrt{2}\;m{s}^{-1}}$

Explanation:

Given,

A body having ,

• mass, m = 1 Kg
• Kinetic Energy , K.E = 1 J

Now,

Let's take it's velocity as v.

Also,

We know that,

• $K.E = \frac{1}{2} m {v}^{2}$

Therefore,

Putting the values,

We get,

$= > 1 = \frac{1}{2} \times 1 \times {v}^{2} \\ \\ = > {v}^{2} = 2 \\ \\ = > v = \sqrt{2} \: m {s}^{ - 1}$

Hence,

The required velocity of the body is,

$\large\bold{\sqrt{2}\;m{s}^{-1}}$

Answer 2

Answer:

● When it's speed is 1.4m/s

=> $K.E = 1/2 m {v}^2$

=> $1 = 1/2 × 1 × {v}^2$

=> $2 = {v}^2$

=> ${v}^2 = 2$

=> $v = √2$

or

=> $1.4m/s$