A 1kg object is located at a distance of 7.0 × 10^(8)m from the centre of a larger object whose mass is 2.0 × 10^(30)kg. What is the size of the force acting on the smaller object?
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Step-by-step explanation:
(a) let m1=2×10^30 KG
m2=1 KG
F=Gm1m2/r² ·
((6.67×10^-11)×(2×10^30)×1) / (7×10^8)²
=272.244 N
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