A 1kg object is located at a distance of 8m from the center of a larger object whose 6.0 x 10^20kg. Find the force of gravity.
Answers
Answered by
2
Answer:
6.26 × 10⁸ N
Explanation:
F = Gm₁m₂/d² [ G = gravitational constant = 6.673 × 10⁻¹¹ Nm²kg⁻²]
= (6.673 × 10⁻¹¹ × 1 × 6.0 x 10²⁰)/8² [ m₁ = mass of first object = 1 kg]
= 4 × 10¹⁰/64 [ m₂ = mass of second object = 6.0 x 10²⁰ kg]
= 6.26 × 10⁸ N
Answered by
1
Answer:
Correct option is C)
Given that λ
B
=2λ
A
and T
B
=T
A
−1.5
We know λ=
p
h
from de-Brogliels equation.
and p=
2mT
∴
λ
B
λ
A
=
2mT
A
2mT
B
=
T
A
T
B
λ
B
λ
A
=
2
1
and
T
A
T
B
=
T
A
T
A
−1.5
∴
2
A
=
T
A
T
A
−1.5
squaring both sides,
4
1
=
T
A
T
A
−1.5
, T
A
=4T
A
−6
3T
A
=6, T
A
=2
∴T
B
=T
A
−1.5=2−1.5=0.5
For metal B, Energy of the incident photon is the sum of the kinetic energy and work function.
E=T+ϕ
⇒4.5=0.5+ϕ,
⇒ϕ=4eV
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