Question

A 1L Sample of ammonia gas exerts a pressure of 5.3 atm. What is the pressure when the volume is reduced one-tenth of the original value at the same temperature ?

Answer 1

Given :

Pressure (P₁) = 5.3atm

V₂ = (1/10)V₁

To find :

Pressure (P₂) = ?

Solution :

• We know from boyle’s law P ∝ (1/V)

        P₁V₁ = P₂V₂

• By substituting the values

       5.3 × V₁ = P₂× (V₁/10)

      5.3 = P₂ × (1/10)

      P₂ = 53atm

The pressure when volume is reduced to one-tenth is 53atm