A 2.0-cm-high object is placed perpendicular to the principal axis of a concave mirror.
The distance of the object from the mirror is 30 cm, and its image is formed 60 cm from the mirror, on the same side of the mirror as the object.
Find the height of the image formed.
Answers
Answered by
94
object height (h1) = +2cm
object distance (u)= -30cm
image distance(v) = -60cm
image height (h) = ?
m = -v/u = h /h1
-v/u = h/h1
-(-60)/-30 = h/ -2
-2 = h/-2
4= h
h= 4cm
thus the height of the object = 4cm
hope it helps!!!
object distance (u)= -30cm
image distance(v) = -60cm
image height (h) = ?
m = -v/u = h /h1
-v/u = h/h1
-(-60)/-30 = h/ -2
-2 = h/-2
4= h
h= 4cm
thus the height of the object = 4cm
hope it helps!!!
Anonymous:
correct ur answer
magnification = height of image / height of object
sry i collapsed
Answered by
37
using sing convention and formula......
m = -v/u = hi/ h0
______________________________
hope it will help u
m = -v/u = hi/ h0
______________________________
hope it will help u
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which answer is correct ??? urs or swathika's ?
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