Question

A 2.0 CM tall object is placed perpendicular to the principal axis of a convex lens of focal length 10cm. the distance of the object from the lens 15 cm find the nature position and size of the image also find the magnification
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Answer 1

@nswer .

Given:- Height of the object = +2.0cm .

Focal length = + 10cm .

Object distance => -15 .

Height of the image h = ?

Formula used :- $\dfrac{1}{v}$ = $\dfrac{1}{u}$+$\dfrac{1}{f}$

$\dfrac{1}{v}$ = $\dfrac{1}{-15}$ + $\dfrac{1}{10}$ = $\dfrac {-1}{15}$ +$\dfrac {1}{10}$

$\dfrac{1}{v}$ = $\dfrac{-2+3}{30} = {1}{30}$

V = + 30 cm .

Magnification Formula = > m $\dfrac{h'}{h}$

h' = h $\dfrac{v}{u}$

m = $\dfrac{+30}{-15}$ = -2

Hence , solved ...