A 2.0 cm tall object is placed perpendicular to the principal axis of a concave lens of focal length 15 cm. At what distance from the lens, should the object be placed so that it forms an image 10 cm from the lens? Also find the nature and the size of image formed.
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Answer:
The image is real and inverted. hope it will help you
Explanation:
Given:
h = 2cm
f = 10cm
u = -15cm
now,
(1 / v) - (1/u) = (1 / f)
(1 / v) = (1 / 10) - (1 / 15)
(1 / v) = (3 -2) / 30
(1 / v) = (1 / 30)
v = 30cm
The image is a real
now,
m = (v/u) = (h!/h)
(30 / -15) = (h! / 2)
cross multiply
h! = -4
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