Physics, asked by janunama51, 2 months ago

A 2.0-kg wood block is placed on a frictionless surface. A spring with a force constant of k = 32.0 N/m is attached to the block, and the opposite end of the spring is attached to the fixed support. The spring can be compressed or extended. The equilibrium position is marked as x = 0.00 m. Work is done on the block, pulling it out to x = + 0.02 m. The block is released from rest and it oscillates between x = + 0.02 m and x = −0.02 m. The period of the motion is 1.57 s. Determine the equations of motion of the system (spring and wood block).

Answers

Answered by prajwalchaudhari
3

Answer:

A spring with a force constant of k = 32.0 N/m is attached to the block, and the opposite end of the spring is attached to the fixed support. The spring can be compressed or extended. The equilibrium position is marked as x = 0.00 m. Work is done on the block, pulling it out to x = + 0.02 m. The block is released from rest and it oscillates between x = + 0.02 m and x = −0.02 m. The period of the motion is 1.57

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