Question

A 2.00 kg oxygen is kept in a closed vessel at a temperature of 127 degree Celsius what amount of heat must be supplied to the gas to double The RMS speed of the molecules ​

Answer 1

⚡⚡Here is your answer⚡⚡

E= 3/2× 10^5×2.0×10^-6/.3×10^20

=4.8×10^-22 J

Answer 2

✴ola!!✴

⤵⤵Answer ⤵⤵

Here,

Mass of nitrogen ( m) = 2 × 10^-2 Kg

Increase in temperature (∆T) = 45°C

molecular mass of N2 (M) = 28 g

= 28 × 10^-3 Kg

R = 8.3 J/mol.K

Number of moles (n) = m/M = 2 × 10^-2/28 × 10^-3 = 5/7

molar specific heat at constant pressure ( Cp) = YR/(Y-1) where Y is atomicity of gases . Y = 1.4

Cp = 1.4R/(1.4-1) = 7R/2

So, heat supplied = nCp∆T

= 5/7 × 7/2 × 45 × 8.3

= 933.75 J

tysm❤