A 2.0cm tall object is placed perpendicular to the principal axix of a convex lens of focal length 10cm . The distance of the object from the lens is 15 cm . Find the nature, position and size of the image . Also find its magnification.
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We know that ,
focal length of a convex lens is positive
f=+10cm
the object distance Is also negative
u=-15cm
As per the lens formula,
the image is inverted , enlarged and real
I hope this helps ( ╹▽╹ )
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Answer:
Height of the object $h _{ 0 }$ = +2.0 cm
Focal length f = +10 cm
Object-distance u = -15cm
Image-distance v = ?
1/v - 1/u = 1/f ====>1/v = 1/f + 1/u ===> 1/v = 1/10 + 1/-15
1/v = -2+3/30
1/v = 1/30
v = 30 cm
The positive sign of v shows that the image is formed at a distance of 30 cm on the other side of the optical centre.The image is real and inverted.
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