A^2+1/9A^2= 1 find A-1/3A
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A^2+1/9A^2=1 (given)
A^2+1/(3A) ^2=1
(A+1/3A)^2=1
(A-1/3A)^2 +A*1/3A*2=1
(A-1/3A)^2 =1-2/3
(A-1/3A) ^2=1/3
(A-1/3A) =√1/3
Therefore,
(A-1/3A) =1/√3
Hope it's clear to you mate☺
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