a^2+1/a^2=102 find the value a_1/a
Answers
Answered by
30
a2 + 1/a2 = 102
Subtracting 2(a)(1/a) on both sides,
a2 + 1/a2 - 2(a)(1/a) = 102 - 2(a)(1/a)
We get,
(a - 1/a)2 = 102 - 2
(a - 1/a)2 = 100
a - 1/a = 1001/2
a - 1/a = 10
Subtracting 2(a)(1/a) on both sides,
a2 + 1/a2 - 2(a)(1/a) = 102 - 2(a)(1/a)
We get,
(a - 1/a)2 = 102 - 2
(a - 1/a)2 = 100
a - 1/a = 1001/2
a - 1/a = 10
sakshamprateek:
thanks
Similar questions