a^2+1/a^2=18 find the values of a+1/a and a-1/a
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1
Answer:
a² + 1/a² = 18
(a- 1/a)² +2 = 18
(a - 1/a)² = 18-2 = 16
a- 1/a = √16 = 4
now.
a² +1/a² = 18
(a+1/a)² - 2 = 18
(a+1/a)² = 18+2. = 20
a + 1/a =. √20 = 2√ 5
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