Question

a^2+1/a^2-2-3a+3/a factorise it by grouping method​

Answer 1

a²+1/a²-2-3a+3/a

= (a-1/a)²-3(a-1/a)

Take (a-1/a) as common factor.

= (a-1/a) {(a-1/a)-3)

= (a-1/a) (a-1/a-3).

This is the answer.