Question

(a^2-1)(b^2-1)+4ab Factorise it


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Answer 1

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Answer 2

Answer:

(a-b+2) *(a+b+2)

Step-by-step explanation:

Given

f = (a^2-1)(b^2-1)+4 a b.

Use a^2-b^2 = (a+b) * (a-b)

(a^2-1)  can be written as (a+1) * (a-1)

b^2-1 can be written as (b+1) * (b-1)

now,

(a^2-1)(b^2-1)+4 a b = a^2*b^2 - a^2 - b^2+1 +4 a b

on further solving and taking common from the equation you will get

(a-b+2) *(a+b+2)

Hence the answer is (a-b+2) *(a+b+2)