A(-2.1), b(a,0), c(4.B) and d(1.2) are the vertices of a parallelogram abcd, find the team
b. Hence find the lengths of its sides. Or
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refer to the attachment.....
we know that the diagonals of a parallelogram bisect each other. show the midpoint of every diagonal will be the same. let this midpoint is O
therefore the midpoint of AC and BD is same
midpoint of AC is
=((-2+4)/2,(1+b)/2)
=(1,(1+b)/2)
midpoint of BD is
=((a+1)/2,2/2)
=((a+1)/2,1)
now .... therefore
(a+1)/2=1
=>a=1
and
(b+1)/2=1
=>b=1
the length of its sides are AB and BC
AB=√[(-2-1)²+(1-0)²]
=√10
BC=√[(1-4)²+(0-1)²]=√10
so the parallegram is a rhombus
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