Question

{a^2(1/c2 - 1/b^2)+b^2(1/a^2- 1/c^2)+c^2(1/b^2- 1/a^2)}/{1/bc(1/c-1/b)+1/ca(1/a-1/c)+1/ab(1/b-1/a)}

Answer 1

Step-by-step explanation:

1/a^2 + 1/b^2 + 1/c^2 = 1/ab + 1/bc + 1/can

=> 1/a^2 + 1/b^2 + 1/c^2 - 1/ab - 1/bc - 1/ca = 0

=> 2/a^2 + 2/b^2 + 2/c^2 - 2/ab - 2/bc - 2/can = 0

=> (1/a - 1/b)^2 + (1/b - 1/c)^2 + ( 1/c - 1/a)^2=0

=> 1/a - 1/b = 1/b - 1/c = 1/c - 1/a = 0

=> 1/a = 1/b = 1/c => a = b = c

Answer 2

Answer:

Step-by-step explanation:

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