Math, asked by santoshjaiswal0226, 7 months ago

a={2,10,30,68...} convert in set builder method​

Answers

Answered by Vaishu7917
4

Answer:

A={x:x€N, x^3+x}

Step-by-step explanation:

Let me explain it actually how it is the answer of this sequence.

2 = 1^3+1

10 = 2^3+2

30 = 3^3+3

68 = 4^3+4

130 = 5^3+5

222 = 6^3+6

And so on...

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Answered by yapuramvaishnavi16
0

The set builder form of a set a = {2,10,30,68.....} is a = {c∈N | c = x³ +x , x∈N} when an equation can also be expressed using the set-builder

Given that,

We have to find the set builder form of a set a = {2,10,30,68.....}

We know that,

The set is

a = {2,10,30,68.....}

So,

1³ + 1 = 2

2³ + 2 = 10

3³ + 3 = 30

4³ + 4  = 68 ........

What is set builder form?

Sets with an interval or an equation can also be expressed using the set-builder. This is how the elements of sets are written and represented, frequently in the case of sets with an unlimited number of elements. One (or more) variables from common groups of numbers, such as integers, real numbers, and natural numbers, are used in this.​

So,

a = {c∈N | c = x³ +x , x∈N}

Therefore, the set builder form of a set a = {2,10,30,68.....} is a = {c∈N | c = x³ +x , x∈N}

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https://brainly.in/question/1233994

https://brainly.in/question/54122945

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