Question

a^2+14a+28
please answer me hurry up​

Answer 1

Answer:

The first term is, a2 its coefficient is 1 .

The middle term is, +14a its coefficient is 14 .

The last term, "the constant", is +28

Step-1 : Multiply the coefficient of the first term by the constant 1 • 28 = 28

Step-2 : Find two factors of 28 whose sum equals the coefficient of the middle term, which is 14 .

-28 + -1 = -29

-14 + -2 = -16

-7 + -4 = -11

-4 + -7 = -11

-2 + -14 = -16

-1 + -28 = -29

1 + 28 = 29

2 + 14 = 16

4 + 7 = 11

7 + 4 = 11

14 + 2 = 16

28 + 1 = 29

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

a2 + 14a + 28

Step-by-step explanation:

Hope it's correct thank you please mark me as a brain lies ~♥~