Question

a^2+16a+63 factorise it​

Answer 1

Answer:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "a2" was replaced by "a^2".

STEP

1

:

Trying to factor by splitting the middle term

1.1 Factoring a2-16a+63

The first term is, a2 its coefficient is 1 .

The middle term is, -16a its coefficient is -16 .

The last term, "the constant", is +63

Step-1 : Multiply the coefficient of the first term by the constant 1 • 63 = 63

Step-2 : Find two factors of 63 whose sum equals the coefficient of the middle term, which is -16 .

-63 + -1 = -64

-21 + -3 = -24

-9 + -7 = -16 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and -7

a2 - 9a - 7a - 63

Step-4 : Add up the first 2 terms, pulling out like factors :

a • (a-9)

Add up the last 2 terms, pulling out common factors :

7 • (a-9)

Step-5 : Add up the four terms of step 4 :

(a-7) • (a-9)

Which is the desired factorization

Final result :

(a - 7) • (a - 9)

Step-by-step explanation:

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Answer 2

$\huge\underline\mathrm{AnSwEr}$

${a}^{2} + 16a + 63$

${a}^{2} + 9a + 7a + 63$

$a(a + 9) + 7(a + 9)$

$(a + 9)(a + 7)$

$<marquee>$hope it helps you....❣️