Math, asked by khuleanurag27, 8 months ago

A(2,2), B(-1,2), C(-1,-1), D(2,-1) are the vertices of square find its area. ​

Answers

Answered by reshmabetageri69
2

Step-by-step explanation:

The x-coordinates of the vertices of a square of unit area are the roots of the equation x2−3|x|+2=0 . The y-coordinates of the vertices are the roots of the equation y2−3y+2=0. Then the possible vertices of the square is/are (1,1),(2,1),(2,2),(1,2) (−1,1),(−2,1),(−2,2),(−1,2) (2,1),(1,−1),(1,2),(2,2) (−2,1),(−1,−1),(−1,2),(−2,2)

the area of the triangle whose vertices are A ( 1,-1,2) , B ( 1,2, -1) ,C ( 3, -1, 2) is ________.

Prove that the points A(2, 3), B(−2, 2), C(−1, −2), and D(3, −1) are the vertices of a square ABCD .

Find the area of the triangle whose vertices are A(3,−1,2), B(1,−1,−3)and C(4,−3,1).

The area of the triangle whose vertices are

A(1,−1,2),B(2,1−1)C(3,−1,2) is …….

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Show that the points A(3, 0), B(4, 5), C(-1, 4) and D(-2, -1) are the vertices of a rhombus. Find its area.

(i) Prove the coordinates of the vertices of a triangle.A(1,−1,2),B(2,1,−1),C(3,−1,2)If its area is13−−√Will be the square unit.

(ii) Find the area of a triangle whose verticesA(1,1,2),B(2,3,5)AndC(1,5,5)is.

Find the area of the quadrilateral whose vertices taken in order are A(−5,−3)B(−4,−6)C(2,−1)andD(1,2).

Of A(−2,−1),B(a,0),C(4,b)andD(1,2) are the vertices f a parallelogram, find the values of aandb.

find the area of the quadrilateral ABCD with vertices A(−2,0),B(0,4),C(4,−2),D(2,2)

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(i) A(1,1,2),B(2,3,5) and C(1,5,5)

(ii) A(1,2,3),B(2,-1,4) and C(4,5,-1)

(iii) A(3,-1,2),B(1,-1,-3) and C(4,-3,1)

(iv) A ( 1,-1,2),B(2,1,-1) and C(3,-1,2).

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If A=(1,2) and B=(2,3), then find the number of elements in (A×B)∩(B×A). The following are the steps involved in solving the above problem. Arrange them in sequential order.

(A) (A×B)∩(B×A)=(2,2)

(B) Given A=(1,2) and B=(2,3)

(C) n[)A×B)∩(B×A)]=1

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