Question

A=(2π+2θ), B=(2π-2θ) Q1) if secA=2 what is the value of θ? Q2)B=-1/√3, θ=?​

Answer 1

Answer:

Correct option is

B

6π,611π

Given secx=32

We know that, sec6π=32 also sec(2π−6π)=sec611π=32

Therefore the principal solutions are 6π,611π