Question

a^2−20a+64 please help me factories this.

Answer 1

Step-by-step explanation:

Hope it helps..

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Answer 2

Given equation

$a^{2} -20a+64=0$

Solving, we get,

$a^{2} -20a+64=0$

$\implies a^{2} -16a-4a+64=0$

$\implies a(a-16)-4(a-16)=0$

$\implies (a-4)(a-16)=0$

Now,

$a-4=0\\\implies a = 4$

$a-16=0\\\implies a = 16$

$\boxed{\boxed{\bold{Therefore, \ the \ factorised \ expression \ is \ (a-4)(a-16)}}}}}}}}}$