Question

a^2+22a+105 factorise class 8 ka questions hai​

Answer 1

$a {}^{2} + 22a + 105$

$a {}^{2} + 15a + 7a + 105$

$a(a + 15) + 7(a + 15)$

$(a + 15)(a + 7)$

Answer 2

Answer:

a²+22a+105 (given)

sum=22a

product=105a²

factors of 105=3, 5, 7

Perfect combination: 22a=15a+7a

so, a²+22a+105=a²+15a+7a+105

=a(a+15)+7(a+15)

=(a+7)(a+15) are the factors of given expression