Question

a^2 + 2ab + b^2 - 16 = ( a + b)^2 - 4^2
= ________________.

Answer 1

a^2 + 2ab + b^2 - 16 = ( a + b)^2 - 4^2

= _______?________.

Factorise :

a^2 + 2ab + b^2 - 16

=> ( a + b)² - (4)²

=> ( a + b +4 ) ( a + b - 4 )

a^2 + 2ab + b^2 - 16 = ( a + b)^2 - 4^2

=> ( a + b +4 ) ( a + b - 4 )

HOPE IT HELPS