(a^2+2ab+b^2)-(a^2+2ac+c^2)/2a+b+c
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Answered by
4
Answer:
Step-by-step explanation:
=[(a+b)^2-(a+c)^2]/(2a+b+c)
=[(a+b+a+c)(a+b-a-c)]/[2a+b+c)
=[(2a+b+c)(b-c)]/[2a+b+c]
=b-c
Answered by
0
Answer:
Step-by-step explanation:
=[(a+b)^2-(a+c)^2]/(2a+b+c)
=[(a+b+a+c)(a+b-a-c)]/[2a+b+c)
=[(2a+b+c)(b-c)]/[2a+b+c]
=b-c
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