Math, asked by syedarmaan7887p9llxn, 10 months ago

(a^2+2ab+b^2)-(a^2+2ac+c^2)/2a+b+c

Answers

Answered by adeshrajputtirwa
4

Answer:

Step-by-step explanation:

=[(a+b)^2-(a+c)^2]/(2a+b+c)

=[(a+b+a+c)(a+b-a-c)]/[2a+b+c)

=[(2a+b+c)(b-c)]/[2a+b+c]

=b-c

Answered by amoghkancharlapalli
0

Answer:

Step-by-step explanation:

=[(a+b)^2-(a+c)^2]/(2a+b+c)

=[(a+b+a+c)(a+b-a-c)]/[2a+b+c)

=[(2a+b+c)(b-c)]/[2a+b+c]

=b-c

Similar questions