Math, asked by devchaudhary65, 5 months ago

a^2 - 2ab + b^2 - c^2
a  {}^{2}  - 2ab + b {}^{2}  - c {}^{2}
please solve it

Answers

Answered by anindyaadhikari13
3

Required Answer:-

Given to factorise:

  • a² - 2ab + b² - c²

Solution:

We know that,

★ (a - b)² = a² - 2ab + b²

Therefore,

a² - 2ab + b² - c²

= [a² - 2ab + b²] - (c)²

= (a - b)² - (c)²

Now, we know that a² - b² = (a + b)(a - b).

Using this identity, we will factorise it.

So,

(a - b)² - (c)²

= (a - b + c)(a - b - c)

Hence, the factorised form of the polynomial is (a - b + c)(a - b - c)

Answer:

  • The factorised form of the polynomial is (a - b + c)(a - b - c).
Answered by BrainlyProgrammer
1

TO FACTORISE:-

  • -2ab +-c²

Solution:-

-2ab+-c²

(a²-2ab+b²)-c² //We know (a-b)²=+-2ab

(a-b)²-c² //Taking (a-b) as (x)

x²-c² //We know -b²=(a+b)(a-b)

Therefore,

(x+c)(x-c)

Substituting x....

=>(a-b+c)(a-b-c)

Final answer:-

(a-b+c)(a-b-c)

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