a^2 -2ab+b^2 solve it please
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Answer:
(a-b)^2
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(a+b)²
= (a+b)×(a+b)
= (a+b)(a+b)
= [a×(a+b)]+[b×(a+b)]
= [a(a+b)]+[b(a+b)]
= [{(a×a)+(a×b)}] + [{(b×a)+(b×b)}]
= [(a²)+(ab)] + [(ba)+(b²)]
= (a²)+(ab)+(ba)+(b²)
Since a×b = b×a (commutative property), ba = ab.
= (a²)+(ab)+(ab)+(b²)
= (a²)+(2×ab)+(b²)
= (a²)+(2ab)+(b²)
Without Algebra, proof that (a+b)² is not equal to a²+b²
Let a = 5, and b = 4.
In (a+b)²,
= (5+4)²
= (9)²
= 9×9
= 81,
Whereas in a² + b²
= 5² + 4²
= 25 + 16
= 41.
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