Question

a) 2^2x + 3.2^x - 4 = 0​

Answer 1

Step-by-step explanation:

let 2^x=y_____(i)

squaring both sides

2^2x=y^2

=2y^2+3y-4=0

By quardratic equation

y=-3+-square root 3^2-4(2)(-4)

_____________________

2(2)

y=-3+-square root9+32

________________

4

y=-3+-square root41

_______________

4

put the value of y in (i)

2^x=-3+-square root41

______________

4

2^x=-3+square root41. 2^x=-3-square root 41

_____________. _____________

4. 4

not possible

Answer 2

Answer:

x = 0

Step-by-step explanation:

given

2^2x+3.2^x-4=0

(2^x) ^2+3.(2^x) -4 =0

Let 2^x = a

now,

or, (a) ^2+3a -4 =0

or, a^2 +3a -4 =0

or, a^2+(4-1) a -4 =0

or, a(a+4) - 1(a+4) =0

or, ( a-1) (a+4) =0

either a + 4 =0

or, a = -4 Not possible value.

either a- 1 =0

or, a = 1

:. 2^x = ( 2)° [ a = 2^x]

so, x = 0.