Math, asked by amit3509, 11 months ago

(a) 2/3,1/3
(b) 21,
3
(a) 2,8,5
The sum of three integers in AP is 15 and their product is 80. The integers are
(b) 8, 2,5
(c) 2,5,8
(d) 8.​

Answers

Answered by aprilfool
0

Answer:

the correct answer is b

Step-by-step explanation:

BCZ 8*2*5=16*5,80

Answered by st712
1

Answer:(c)2,5,8

Step-by-step explanation:let a1 a2 and a3 be the integers

ATQ:

a1+a2+a3=15

a+a+d+a+2d=15 (an=a+(n-1)d)

3a+3d=15

a+d=5

d=5-a .........eq(1)

a(a+d)(a+2d)=80

a^3+2a^2d+a^2d+2ad^2=80

a^3+3a^2d+2ad^2=80

a^3+3a^2(5-a)+2a(5-a)^2=80 (from eq (1)

a^3+15a^2-3a^3+2a(25+a^2-10a)=80

15a^2-2a^3+50a+2a^3-20a^2=80

50a-5a^2=80

10a-a^2=16

a^2-10a+16=0

a=8 of a=2

d=-3 or a=3

Required integers = 2,5,8

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